-16x^2+320x+25600=0

Solution for -16x^2+320x+25600=0 equation:

-16x^2+320x+25600=0

a = -16; b = 320; c = +25600;
Δ = b2-4ac
Δ = 3202-4·(-16)·25600
Δ = 1740800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1740800}=\sqrt{102400*17}=\sqrt{102400}*\sqrt{17}=320\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(320)-320\sqrt{17}}{2*-16}=\frac{-320-320\sqrt{17}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(320)+320\sqrt{17}}{2*-16}=\frac{-320+320\sqrt{17}}{-32}
$